Haryana PMT Haryana PMT Solved Paper-2004

  • question_answer
    The formation of ice is started in a lake with water at \[0{}^\circ C\]. When the atmospheric temperature is -\[10{}^\circ C\]. If time taken for 1 cm of ice to be formed is 7 hours, the time taken for the thickness of ice to increase from 1 cm to 2 cm is :

    A)  less than 7 hours

    B)  7 hours

    C)  more than 14 hours

    D)  more than 7 hours but less than 14 hours

    Correct Answer: C

    Solution :

                                             We know that the time of formation of ice in a lake from thickness \[{{y}_{1}}\] to \[{{y}_{2}}\]is directly proportional to                 \[({{y}_{2}}^{2}-{{y}_{1}}^{2})\propto {{t}_{1}}\]            ??..(i) Again,      \[({{y}_{3}}^{2}-{{y}_{2}}^{2})\propto {{t}_{2}}\]        ??.(ii) Given:  \[{{y}_{1}}=0cm,\,\,{{y}_{2}}=1cm\] \[{{y}_{3}}=2cm,\,\,{{t}_{1}}=7\,hour,\,{{t}_{2}}=?\] From (i) and (ii), we get                 \[\frac{{{y}_{3}}^{2}-{{y}_{2}}^{2}}{{{y}_{2}}^{2}-{{y}_{1}}^{2}}=\frac{{{t}_{2}}}{7}\] or            \[\frac{{{2}^{2}}-{{1}^{2}}}{{{1}^{2}}-{{0}^{2}}}=\frac{{{t}_{2}}}{7}\] or            \[\frac{3}{1}=\frac{{{t}_{2}}}{7}\] Hence,  \[{{t}_{2}}=7\times 3=21hour\]


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