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Haryana PMT Haryana PMT Solved Paper-2004

  • question_answer
    A body of uniform cross-sectional area floats in a liquid of density thrice its value. The fraction of exposed height will be:

    A)  2/3                                       

    B)  5/6

    C)  1/6                                       

    D)  1/3

    Correct Answer: A

    Solution :

                                             Here area is uniform, so portion of immersed height \[=\frac{1}{3}\] (Here: the ratio of density of body and density of water \[=\frac{1}{3}\]) Therefore, fraction of exposed height will                                 \[1-\frac{1}{3}=\frac{2}{3}\]


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