A) 5m/s
B) 14m/
C) 17.5m/s
D) 10 m/s
Correct Answer: D
Solution :
\[F=\frac{-\partial u\hat{i}}{\partial x}\frac{-\partial u\hat{j}}{\partial y}\] \[=7\hat{i}-24\hat{j}\] \[\therefore \] \[{{a}_{x}}=\frac{{{F}_{x}}}{m}=\frac{7}{5}=1.4m/{{s}^{2}}\]along positive x-axis \[{{a}_{y}}=\frac{{{F}_{y}}}{m}=-\frac{24}{5}=4.8m/{{s}^{2}}\]along negative y-axis- \[\therefore \] \[{{v}_{x}}={{a}_{x}}t=1.4\times 2=2.8m/s\] and \[{{v}_{y}}=4.8\times 2=9.6m/s\] \[\therefore \] \[v=\sqrt{v_{x}^{2}+v_{y}^{2}}=10m/s\]
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