A) \[f\]
B) \[f/2\]
C) \[2f\]
D) zero
Correct Answer: C
Solution :
If \[x=A\,\sin \,\,\omega t\] Then, \[PE=\frac{1}{2}m\,{{A}^{2}}\,{{\omega }^{2}}\,{{\sin }^{2}}\omega t\] \[\therefore \] \[PE=\frac{1}{2}m{{A}^{2}}{{\omega }^{2}}\left( \frac{1-\cos \,2\omega t}{2} \right)\] \[\therefore \] \[\omega =2\omega \] or \[2\pi f=2\times 2\pi f\] \[f=2f\]
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