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Haryana PMT Haryana PMT Solved Paper-2006

  • question_answer
    In the nuclear reaction : \[^{\text{2}}\text{H}{{\text{e}}^{\text{4}}}{{\text{+}}_{\text{z}}}{{\text{X}}^{\text{A}}}{{\xrightarrow{{}}}_{\text{z+2}}}{{\text{Y}}^{\text{A+3}}}{{\text{+}}_{\text{z}}}{{\text{M}}^{\text{A }\!\!\!\!\text{ }}}\]where M denotes :

    A)                  electron                             

    B)  positron

    C)                  proton                                

    D)  neutron

    Correct Answer: D

    Solution :

                    Applying charge and mass conservation \[4+A=A+3+A\]                 \[\Rightarrow \]               \[A=1\]                                 \[2+z=z+2+z\]  \[\Rightarrow \] \[z=0\] Hence, M is neutron.


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