A) \[4.07\times {{10}^{4}}V\]
B) \[8.2\times {{10}^{4}}V\]
C) \[8.2\times {{10}^{3}}V\]
D) \[4.07\times {{10}^{5}}V\]
Correct Answer: D
Solution :
\[\lambda =\frac{h}{\sqrt{2mqV}}\]\[{{({{10}^{-13}})}^{2}}=\frac{{{(6.6\times {{10}^{-34}})}^{2}}}{2\times 1.67\times {{10}^{-27}}\times 1.6\times {{10}^{-19}}V}\]\[V=8.2\times {{10}^{4}}V\]
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