question_answer

Number of isomers possible for \[{{C}_{4}}{{H}_{8}}O\] is

A)  \[3\]                                    

B)  \[4\]

C)  \[5\]                                    

D)  \[6\]

Correct Answer: D

Solution :

                There are 6 isomers possible for the compounds having molecular formula \[{{C}_{4}}{{H}_{5}}O\]which are as follows: \[\underset{(I)}{\mathop{C{{H}_{3}}C{{H}_{2}}\overset{O}{\mathop{\overset{||}{\mathop{C}}\,}}\,-O{{H}_{3}}}}\,\] \[\underset{(II)}{\mathop{C{{H}_{2}}C{{H}_{2}}C{{H}_{2}}CHO}}\,\]   and        \[\underset{(vi)}{\mathop{C{{H}_{2}}=CH-C{{H}_{2}}C{{H}_{2}}OH}}\,\]