A) \[-{{1.86}^{o}}C\]
B) \[{{1.86}^{o}}C\]
C) \[-{{3.92}^{o}}C\]
D) \[{{2.42}^{o}}C\]
Correct Answer: A
Solution :
Molality of cane sugar solution \[=\frac{342}{342\times 1}=1m\] We know that, \[\Delta {{T}_{f}}={{K}_{f}}.m\] \[=1.86\times 1m\] \[={{1.86}^{o}}\] Hence, freezing point of solution \[=0.00-(1.86)=-{{1.86}^{o}}C\]
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