Haryana PMT Haryana PMT Solved Paper-2006

  • question_answer
    In the electrolysis of water one faraday of electrical energy would evolve:

    A)  \[1mole\]of oxygen

    B)  1 gram-atom of oxygen

    C)  8 g of oxygen

    D)  \[22.4\text{ }L\]of oxygen

    Correct Answer: C

    Solution :

                    Hydrolysis of water can be represented by the following equations, \[2{{H}_{2}}O{{O}_{2}}+4{{H}^{+}}+4{{e}^{-}}\] \[\because \] 4 faraday of charge liberate \[{{O}_{2}}=32g\] \[\therefore \] 1 faraday of charge liberate \[{{O}_{2}}=\frac{32}{4}\]                                                 \[=8g\]


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