Haryana PMT Haryana PMT Solved Paper-2007

  • question_answer
    If in the following figure, height of object is \[{{H}_{1}}=+2.5cm,\] then height of image H2 formed is

    A)  -5 cm                                   

    B)  +5 cm

    C)  +7.5 cm                              

    D)  -7.5cm

    Correct Answer: A

    Solution :

                    Key Idea Magnification is ratio of size of image to that of object. Here,   \[u=-1.5f,\,\,f=-f\] From concave mirror formula,                 \[\frac{1}{f}=\frac{1}{v}+\frac{1}{u}\] we have,                 \[\frac{1}{(-f)}=\frac{1}{v}+\frac{1}{(-1.5f)}\] \[\therefore \]  \[\frac{1}{v}=-\frac{1}{3f}\] or            \[v=-3f\] Now, magnification in mirror is given by                 \[m=\frac{I}{O}=\frac{v}{-u}\] where \[I\] is size of image, and0 is size of object. Here,    \[O=+2.5cm\] \[\therefore \]  \[\frac{I}{2.5}=\frac{-3f}{-(1.5f)}\] \[\therefore \]  \[I=-5cm\] Note In case of a concave mirror, magnification may be positive or negative, but in case of convex mirror magnification is positive only.


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