Haryana PMT Haryana PMT Solved Paper-2007

  • question_answer
    If\[{{B}_{H}}=\frac{1}{\sqrt{3}}{{B}_{v,}}\] find angle of dip. (where symbols have their usual meanings)

    A) \[60{}^\circ \]                                   

    B) \[30{}^\circ \]

    C) \[45{}^\circ \]

    D) \[90{}^\circ \]

    Correct Answer: A

    Solution :

                    Magnetic dip or magnetic inclination at a place is defined as the angle which the direction of total strength of earths magnetic field makes with a horizontal line in magnetic meridian. It is the angle by which total intensity of earths magnetic field dips or comes up out of the horizontal plane. It is represented by 8. Magnetic dip or magnetic inclination is given by,                   \[\tan \delta =\frac{{{B}_{V}}}{{{B}_{H}}}\]      ...(i) where \[{{B}_{V}}\] and \[{{B}_{H}}\] are vertical and horizontal components of earths magnetic field, respectively.          Given,       \[{{B}_{H}}=\frac{1}{\sqrt{3}}{{B}_{V}}\]    \[\therefore \]  \[\frac{{{B}_{V}}}{{{B}_{H}}}=\sqrt{3}\]              ??(ii) From Eqs. (i) and (ii), we get                 \[\tan \delta =\sqrt{3}\] \[\therefore \]  \[\delta ={{60}^{o}}\]    


You need to login to perform this action.
You will be redirected in 3 sec spinner