A) \[x={{K}_{sp}}\]
B) \[{{x}^{2}}=\sqrt{{{K}_{sp}}}\]
C) \[x=\sqrt{{{K}_{sp}}}\]
D) \[x=\frac{{{K}_{sp}}}{2}\]
Correct Answer: C
Solution :
\[BaC{{O}_{3}}\xrightarrow{{}}B{{a}^{2+}}+CO_{3}^{2-}\] If solubility = x, then \[{{K}_{sp}}={{x}^{2}}\] \[x=\sqrt{{{K}_{sp}}}\]
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