A) 25.8 MeV
B) 23.6 MeV
C) 19.2 MeV
D) 30.2 MeV
Correct Answer: B
Solution :
The reaction can be written as \[_{1}{{H}^{2}}{{+}_{1}}{{H}^{2}}{{\xrightarrow{{}}}_{2}}H{{e}^{4}}+energy\] The energy released in the reaction is difference of binding energies of daughter and parent nuclei. Hence, energy released = binding energy of \[_{2}H{{e}^{4}}\] \[-2\times \] binding energy of \[_{1}{{H}^{2}}\] \[=28-2\times 2.2=23.6MeV\]
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