Haryana PMT Haryana PMT Solved Paper-2008

  • question_answer
    The time of reverberation of a room A is one second. What will be the time (in second) of reverberation of a room, having all the. dimensions double of those of room A?

    A)  2                                            

    B)  4

    C)  \[\frac{1}{2}\]                                  

    D)  1

    Correct Answer: A

    Solution :

                    Sabines formula for reverberation time is \[T=\frac{0.16V}{\Sigma a\,s}\]where V is volume of hall in \[{{m}^{3}}\].                 \[\Sigma as={{a}_{1}}{{s}_{1}}+{{a}_{2}}{{s}_{2}}+........=\]total absorption of the hall (room) Here, \[{{s}_{1}},{{s}_{2}},{{s}_{3}}...........\]are surface areas of the absorbers and \[{{a}_{1}},{{a}_{2}},{{a}_{3}}...........\] are their respective absorption coefficients. \[\therefore \]  \[\frac{T}{T}=\frac{V}{s}\times \frac{s}{V}\]                 \[=\frac{{{(2)}^{3}}}{{{(2)}^{2}}}=\frac{8}{4}=2\] Hence, \[T=2T=2\times 1=2s\]


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