Haryana PMT Haryana PMT Solved Paper-2008

  • question_answer
    An electric dipole of moment \[\overrightarrow{\text{P}}\] is lying along              a uniform electric field \[\overrightarrow{\text{E}\text{.}}\]The work done in rotating the dipole by 90° is

    A) \[\sqrt{2}pE\]                                   

    B) \[\frac{pE}{2}\]

    C) \[2pE\]                                

    D)  \[pE\]

    Correct Answer: D

    Solution :

                    When an electric dipole is placed in an electric field \[\overrightarrow{E}\], a torque \[\overrightarrow{\tau }=\overrightarrow{p}\times \overrightarrow{E}\] acts on it. This torque tries to rotate the dipole through an angle \[\theta \]. If the dipole is rotated from an angle .\[{{\theta }_{1}}\]to \[{{\theta }_{2}}\] then work done/by external force is given by \[W=pE(\cos {{\theta }_{1}}-\cos {{\theta }_{2}})\]        ...(i) putting \[{{\theta }_{1}}={{0}^{o}},\,{{\theta }_{2}}={{90}^{o}}\] in the Eq. (i), we get                 \[W=pE(\cos {{0}^{o}}-\cos {{90}^{o}})\]                 \[=pE(1-0)\]                 \[=pE\]


You need to login to perform this action.
You will be redirected in 3 sec spinner