A) \[\overrightarrow{\text{P}}={{\text{ }\!\!\varepsilon\!\!\text{ }}_{\text{0}}}\overrightarrow{\text{E}}\text{+}\overrightarrow{\text{D}}\]
B) \[\overrightarrow{\text{P}}=\overrightarrow{\text{D}}\text{+}\overrightarrow{\text{E}}\]
C) \[\overrightarrow{\text{D}}={{\text{ }\!\!\varepsilon\!\!\text{ }}_{\text{0}}}\overrightarrow{\text{E}}\text{+}\overrightarrow{\text{P}}\]
D) \[\overrightarrow{\text{E}}\text{+}\overrightarrow{\text{D}}\text{=}\overrightarrow{\text{P}}\]
Correct Answer: C
Solution :
The relation between electric field vector \[\overrightarrow{E}\], the displacement vector \[\overrightarrow{D}\] and the polarization vector \[\overrightarrow{P}\] for a dielectric placed in electric field \[\overrightarrow{E}\] is given by \[\overrightarrow{D}={{\varepsilon }_{0}}\,\overrightarrow{E}+\overrightarrow{P}\].
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