question_answer

The number of nodal planes in \[{{p}_{x}}\]. orbital is

A)  \[1\]                                    

B)  \[2\]

C)  \[3\]                                    

D)  \[0\]

Correct Answer: A

Solution :

                Number of nodal planes \[=l\] For \[{{p}_{x}}\]orbital, \[l=1\] \[\therefore \] Number of nodal planes = 1 (c)                     (d) Electronegativity \[\propto \frac{1}{nucleophilicity}\] \[\therefore \] \[CH_{3}^{-}\] has the highest nucleophilicity.