A) 3-phenyl-l-butene
B) 1-phenyl-2-butene
C) 2-phenyl-l-butene
D) 1, 1-diphenyl-l-propene
Correct Answer: B
Solution :
The compound which has at least one double bond and the groups attached with double bonded carbon atoms are different, exhibits geometrical isomerism. \[C{{H}_{3}}CH=CHC{{H}_{2}}{{C}_{6}}{{H}_{5}}\]exhibits geometrical isomerism. \[\underset{\begin{smallmatrix} 1-phenyl-2-butene \\ cis\,form \end{smallmatrix}}{\mathop{\begin{matrix} {{H}_{3}}C & {} & C{{H}_{2}}{{C}_{6}}{{H}_{5}} \\ {} & C=C & {} \\ H & {} & H \\ \end{matrix}}}\,\] \[\underset{trans\,form}{\mathop{\begin{matrix} {{H}_{3}}C & {} & H \\ {} & C=C & {} \\ H & {} & C{{H}_{2}}{{C}_{6}}{{H}_{5}} \\ \end{matrix}}}\,\]
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