A) 0.01 A
B) 0.02 A
C) 0.03 A
D) 0.04 A
Correct Answer: B
Solution :
For an ammeter \[\frac{{{i}_{g}}}{i}=\frac{S}{G+S}\] \[\Rightarrow \] \[{{i}_{g}}G=(i-{{i}_{g}})S\] \[\therefore \] \[{{i}_{g}}G=(0.03-{{i}_{g}})4r\] ???(i) and \[{{i}_{g}}G=(0.06-{{i}_{g}})r\] ...(ii) From Eqs. (i) and (ii) \[0.12-4{{i}_{g}}=0.06-{{i}_{g}}\] \[\Rightarrow \] \[{{i}_{g}}=0.02A\]
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