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Haryana PMT Haryana PMT Solved Paper-2010

  • question_answer
    To break a wire of 1 m length, minimum 40 kg weight is required. Then the wire of the same material of double radius and 6 m length will require breaking

    A)  80 kg weight    

    B)  240 kg weight

    C)  200 kg weight                  

    D)  160 kg weight

    Correct Answer: D

    Solution :

                    Breaking force = Breaking stress \[\times \]area of cross-section of wire \[\therefore \]Breaking force \[\propto {{r}^{2}}\] (breaking distance is constant)               If radius becomes doubled, then breaking force will become 4 times ie, \[40\times 4=160\text{ }kg-wt.\].


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