A) \[\frac{\Delta p}{200}\]
B) \[\frac{\Delta p}{199}\]
C) \[199\Delta p\]
D) \[400\Delta p\]
Correct Answer: C
Solution :
de-Broglie wavelength \[\lambda =\frac{h}{p}\] \[\Rightarrow \] \[\lambda -\frac{0.5\lambda }{100}=\frac{h}{p+\Delta p}\] \[\Rightarrow \] \[\frac{199\lambda }{200}=\frac{h}{p+\Delta p}=\frac{199h}{200p}\] \[\Rightarrow \] \[p+\Delta p=\frac{200}{199}p\] \[\Rightarrow \] \[p=199\Delta p\]
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