A) \[2.3\times {{10}^{10}}\]
B) \[1.15\times {{10}^{10}}\]
C) \[1\times {{10}^{5}}\]
D) None of these
Correct Answer: B
Solution :
Optical source frequency \[f=\frac{c}{\lambda }=\frac{3\times {{10}^{8}}}{1.3\times {{10}^{-6}}}=2.3\times {{10}^{14}}Hz\] \[\therefore \] Number of channels or subscribers \[=\frac{2.3\times {{10}^{14}}}{20\times {{10}^{3}}}=1.15\]
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