A) \[\frac{V}{4}\]
B) 16 V
C) \[\frac{V}{8}\]
D) (d\[\frac{V}{12}\]
Correct Answer: D
Solution :
Rate of flow under a constant pressure head \[V=\frac{\pi p{{r}^{4}}}{8\eta l}\] \[\Rightarrow \] \[V\propto \frac{{{r}^{4}}}{l}\] \[\Rightarrow \] \[\frac{{{V}_{2}}}{{{V}_{1}}}={{\left[ \frac{{{r}_{2}}}{{{r}_{1}}} \right]}^{4}}\times \frac{{{l}_{1}}}{{{l}_{2}}}={{\left[ \frac{1}{2} \right]}^{4}}\times \frac{1}{2}\] \[\Rightarrow \] \[{{V}_{2}}=\frac{{{V}_{1}}}{32}=\frac{V}{32}\]
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