A) \[124S\text{ }c{{m}^{2}}\]
B) \[124c{{m}^{-1}}\]
C) \[124\text{ }oh{{m}^{-1}}\text{ }c{{m}^{2}}\text{ }equi{{v}^{-1}}\]
D) \[124S\text{ }c{{m}^{2}}\text{ }mo{{l}^{-1}}\]
Correct Answer: D
Solution :
Molar conductivity, \[{{\Lambda }_{m}}=\frac{k\times 1000}{C}\] Given, \[k=0.0248\,S\,\,c{{m}^{-1}},\]\[C=0.20M\] \[\therefore \] \[{{\Lambda }_{m}}=\frac{0.0248\times 1000}{0.20}\] \[=124\,\,S\,c{{m}^{2}}mo{{l}^{-1}}\]
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