A) 0.2938cm
B) 0.8938cm
C) 0.6938cm
D) None of these
Correct Answer: A
Solution :
For wider limb, \[\,{{h}_{1}}\frac{2T}{{{r}_{1}}dg}\] For the narrow limb, \[\,{{h}_{2}}\frac{2T}{{{r}_{2}}dg}\] \[\,{{h}_{2}}-{{h}_{1}}\frac{2T}{dg}\left( \frac{1}{{{r}_{2}}}-\frac{1}{{{r}_{1}}} \right)\] \[\,=\frac{2\times 72}{1\times 980}\left( \frac{1}{0.25}-\frac{1}{0.5} \right)\] \[\,=\frac{2\times 72}{980}\times \frac{0.25}{0.25\times 0.5}=0.2938\,cm\]
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