A) \[{{10}^{-8}}J{{m}^{-3}}\]
B) \[{{10}^{-7}}J{{m}^{-3}}\]
C) \[{{10}^{-}}^{6}J{{m}^{-3}}\]
D) \[{{10}^{-5}}J{{m}^{-3}}\]
Correct Answer: A
Solution :
\[{{U}_{E}}=\frac{1}{2}\varepsilon {{0}_{{{E}^{2}}}}\] \[=\frac{1}{2}\times 8.85\times {{10}^{-12}}\times {{(50)}^{2}}\] \[\approx {{10}^{8}}J{{m}^{-3}}\]
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