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Haryana PMT Haryana PMT Solved Paper-2011

  • question_answer
    A solenoid 600 mm long has 50 turns on it and is  wound on an iron rod of 7.5 mm radius. Find     the flux through the solenoid when the current          in it is 3 A. The relative permeability of iron is      600.

    A)                  1.66Wb                               

    B)  1.66 N Wb

    C)                  1.66 m Wb                         

    D)  1.66 \[\mu \] Wb

    Correct Answer: C

    Solution :

                    \[\theta ={{\mu }_{r}}{{\mu }_{0}}\frac{{{N}^{2}}}{l}Ai\]                 \[=\frac{600\times 4\pi \times {{10}^{7}}\times 50\times \pi {{(7.5\times {{10}^{-3}})}^{2}}\times 3}{6\times {{10}^{10-1}}}\]                 \[=1.66\times {{10}^{-3}}Wb\]                 \[=1.66mWb\]


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