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Haryana PMT Haryana PMT Solved Paper-2011

  • question_answer
    A transformer has an efficiency of 80%. It works at 4 kW and 100 V. If secondary voltage is 240 V, the current in primary coil is

    A)                  0.4 A                                    

    B)  4 A

    C)                  10 A                                     

    D)  40 A

    Correct Answer: D

    Solution :

                    \[As{{I}_{p}}{{E}_{p}}={{P}_{i}}\]                 \[\therefore \]  \[{{I}_{p}}=\frac{{{P}_{i}}}{{{E}_{p}}}=\frac{4000}{100}=40A\]


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