A) 12 and 4
B) 12 and 5
C) 16 and 4
D) 16 and 5
Correct Answer: B
Solution :
\[Cr(Z=24):1{{s}^{2}},2{{s}^{2}}2{{p}^{6}},3{{s}^{2}}3{{p}^{6}}3{{d}^{5}},4{{s}^{1}}\] For p-orbital \[l=1\] and for d-orbital \[l=2\] Hence, for \[l=1\], total number of electrons =12 and for \[l=2\], total number of electrons = 5
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