A) \[4.521\overset{\text{o}}{\mathop{\text{A}}}\,~\]
B) \[5.783\overset{\text{o}}{\mathop{\text{A}}}\,~\]
C) \[5.213\overset{\text{o}}{\mathop{\text{A}}}\,~\]
D) \[4.976\overset{\text{o}}{\mathop{\text{A}}}\,~\]
Correct Answer: B
Solution :
Molecular mass of \[CuCl=99\] For fee structure, \[Z=4\] \[d=\frac{Z\times M}{{{a}^{3}}\times {{N}_{0}}}\] \[3.4=\frac{4\times 99}{{{a}^{3}}\times 6.023\times {{10}^{23}}}\] \[{{a}^{3}}=\frac{4\times 99}{3.4\times 6.023\times {{10}^{23}}}\] \[a=5.783\times {{10}^{-8}}cm=5.783\overset{\text{o}}{\mathop{\text{A}}}\,\]
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