| A | B | Y |
| 0 | 0 | 1 |
| 1 | 0 | 1 |
| 0 | 1 | 1 |
| 1 | 1 | 0 |
A) NAND
B) AND
C) XOR
D) NOT
Correct Answer: A
Solution :
The given truth table is the NOT of an AND gate, hence, it is a NAND gate. That is, the output is 1 when NOT (A AND B are 1), as shown in the truth table:| Input | Output | |
| A | B | A NAND B |
| 0 | 0 | 1 |
| 1 | 0 | 1 |
| 0 | 1 | 1 |
| 1 | 1 | 0 |
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