J & K CET Engineering J and K - CET Engineering Solved Paper-2003

  • question_answer
    If for a gas \[\frac{R}{{{C}_{V}}}=0.67,\] this gas is made up of molecules which "are

    A)  monoatomic

    B)  diatomic

    C)  polyatomic

    D)  mixture of diatomic and polyatomic molecules

    Correct Answer: A

    Solution :

    From Mayor's formula, \[{{C}_{P}}-{{C}_{V}}=R\]              .....(i) where R is gas constant. Also,             \[\gamma =\frac{{{C}_{P}}}{{{C}_{V}}}\] .....(ii) From Eqs. (i) and (ii), we have \[\gamma -1=\frac{R}{{{C}_{V}}}\] Given,       \[\frac{R}{{{C}_{V}}}=0.67\] \[\therefore \] \[\gamma =0.67+1=1.67\] Hence, gas is monoatomic.


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