A) zero
B) \[\frac{\pi }{4}\]
C) \[\pi \]
D) \[\frac{\pi }{2}\]
Correct Answer: D
Solution :
Magnetic field exerts force \[(\vec{F})\] on moving charge (q) is given by \[\vec{F}=q\vec{v}\times \vec{B}=q\vec{v}\vec{B}\,\sin \theta \] Where \[\vec{v}\] is velocity, \[\vec{B}\] the magnetic field, and \[\theta \] the angle between the two. F is maximum when \[\sin \theta \] is maximum. Therefore, \[\theta =\frac{\pi }{2},\,\,\,\sin \frac{\pi }{2}=1\]
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