A) \[{{C}_{6}}{{H}_{5}}N{{H}_{3}}Cl\]
B) \[La{{(N{{O}_{3}})}_{3}}\]
C) glucose
D) \[Ca{{(N{{O}_{3}})}_{2}}\]
Correct Answer: C
Solution :
Glucose is a non-electrolyte, hence\[i=1,\] while others are electrolyte, hence \[i>1.\] \[\therefore \] \[\Delta {{T}_{f}}=i\times {{k}_{f}}\times \text{molality}\] The value of \[\Delta {{T}_{f}}\]is lowest for glucose, hence its freezing point is maximum.
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