J & K CET Engineering J and K - CET Engineering Solved Paper-2003

  • question_answer
    \[{{N}_{2}}\]and\[{{O}_{2}}\]are converted into\[N_{2}^{+}\]and \[O_{2}^{+}\]respectively. Which of the following is .not correct?

    A)  In \[{{N}_{2}}^{+},\]the N?N bond weakens

    B)  In \[O_{2}^{+},O-O\] bond order increases

    C)  ln \[{{O}_{2}}^{+},\] paramagnetism decreases

    D)  \[{{\text{N}}_{\text{2}}}^{\text{+}}\]becomes diamagnetic

    Correct Answer: D

    Solution :

     \[{{N}_{2}}:KK\] \[{{(\sigma 2s)}^{2}}{{(\sigma *2s)}^{2}}{{(\pi 2{{p}_{x}})}^{2}}{{(\pi 2{{p}_{y}})}^{2}}{{(\sigma 2{{p}_{z}})}^{2}}\] Bond order \[=\frac{{{N}_{b}}-{{N}_{a}}}{2}=\frac{8-2}{2}=3\] It is diamagnetic in nature. \[{{N}_{2}}^{+}:KK{{(\sigma 2s)}^{2}}{{(\sigma *2s)}^{2}}{{(\pi 2{{p}_{x}})}^{2}}{{(\pi 2{{p}_{y}})}^{2}}{{(\sigma 2{{p}_{z}})}^{1}}\]\[\text{Bond}\,\text{order}=\frac{7-2}{2}=2.5\] It is paramagnetic in nature.


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