A) \[{{H}_{3}}C-C\equiv CH\]
B) \[{{H}_{3}}C-C\equiv C-C{{H}_{3}}\]
C) \[{{H}_{2}}C=C{{H}_{2}}\]
D) \[{{H}_{3}}C-C{{H}_{3}}\]
Correct Answer: A
Solution :
The H-atoms of terminal alkyne \[(ie,{{H}_{3}}C-C\equiv CH)\] is weakly acidic. \[C{{H}_{3}}\equiv CH+Na{{H}_{2}}\xrightarrow{\text{liq}\text{.N}{{\text{H}}_{\text{3}}}}{{H}_{3}}C-CH\equiv CNa\] \[+\,N{{H}_{3}}\]
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