A) \[13\]
B) \[39\]
C) \[78\]
D) \[91\]
Correct Answer: D
Solution :
The number of terms in \[{{(a+b+c)}^{12}}\] is \[^{12+2}{{C}_{2}}{{=}^{14}}{{C}_{2}}\] \[=\frac{14\times 13}{2\times 1}\] \[=91\]You need to login to perform this action.
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