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J & K CET Engineering J and K - CET Engineering Solved Paper-2003

  • question_answer
    \[\underset{h\to \frac{x}{4}}{\mathop{\lim }}\,\frac{\tan \,x-1}{x-\frac{\pi }{4}}\]is equal to

    A)  \[1\]

    B)  \[1/2\]

    C)  \[2\]

    D)  \[0\]

    Correct Answer: C

    Solution :

    \[\underset{x\to \frac{\pi }{4}}{\mathop{lim}}\,\,\frac{\tan \,x-1}{x-\frac{\pi }{4}}\] \[\left( \frac{0}{0}\,\,form \right)\] Applying I/Hospital's rule,                                                 \[=\underset{x\to \frac{\pi }{4}}{\mathop{\lim }}\,\,\frac{{{\sec }^{2}}\,x}{1}=2\]c


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