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J & K CET Engineering J and K - CET Engineering Solved Paper-2003

  • question_answer
    The equation of the directrix of the parabola \[{{y}^{2}}+4y+4x+2=0\] is

    A)  \[-1\]        

    B)  \[x=1\]

    C)  \[x=-3/2\]     

    D)  \[x=3/2\]

    Correct Answer: D

    Solution :

    Given equation can be rewritten as \[{{(y+2)}^{2}}=-4\left( x-\frac{1}{2} \right)\] \[\Rightarrow \] s\[{{Y}^{2}}=-4X,\] where \[Y=y+2\] and \[X=x-\frac{1}{2}\]. The equation of directrix is \[X=1\]. \[\therefore \]    \[x-\frac{1}{2}=1\,\,\,\Rightarrow \,\,\,x=\frac{3}{2}\]


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