J & K CET Engineering J and K - CET Engineering Solved Paper-2004

  • question_answer
    A source of emf \[E=15V\] and having negligible internal resistance, is connected to a variable resistance, so that the current in the circuit increases with time as \[I=1.2t+3\]. Then, the total charge that will flow in first \[5\text{ }s\]will be

    A)  \[10\text{ }C\]         

    B)  \[20\text{ }C\]

    C) \[30\text{ }C\]          

    D)  \[40\text{ }C\]

    Correct Answer: C

    Solution :

    Charge (q) is given by \[q=\int{Idt}\] Given,        \[I=1.2t+3\] Integrating the expression using \[\int{{{x}^{n}}dx}\,=\frac{{{x}^{n+1}}}{n+1},\] we have \[q=\int{Idt}=1.2\int{t\,\,dt\,\,+3\int{dt}}\] \[q=1.2\left[ \frac{{{t}^{2}}}{2} \right]_{0}^{5}+3[t]_{0}^{5}\] \[q=\frac{1.2}{2}\times 25+3\times 5\] \[q=15+15=30C\]


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