A) \[80\,\,cm\]
B) \[8\,\,cm\]
C) \[0.8\,\,cm\]
D) \[80\,\,m\]
Correct Answer: B
Solution :
From the theorem of parallel axis, the moment of inertia I is equal to \[I={{I}_{CM}}+M{{a}^{2}}\] where \[{{I}_{CM}}\]where moment of inertia is about centre of mass and a the distance of axis from centre. \[\therefore \] \[I=M{{K}^{2}}+M\times {{(6)}^{2}}\] \[MK_{1}^{2}=M{{K}^{2}}+36M\] \[\Rightarrow \] \[K_{1}^{2}={{K}^{2}}+36\] \[\Rightarrow \] \[{{(10)}^{2}}={{K}^{2}}+36\] \[\Rightarrow \] \[{{K}^{2}}=100-36=64\] \[\Rightarrow \] \[K=8cm\]
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