A) \[N{{O}_{2}}>NO_{2}^{+}>NO_{2}^{-}\]
B) \[NO_{2}^{-}>N{{O}_{2}}>NO_{2}^{+}\]
C) \[NO_{2}^{+}>N{{O}_{2}}>NKO_{2}^{-}\]
D) \[NO_{2}^{+}>NO_{2}^{-}>N{{O}_{2}}\]
Correct Answer: C
Solution :
As the number of unpaired electrons (lone pair of electrons) increases, bond angle decreases. Thus, the decreasing order of bond angle is \[\begin{align} & \text{Species:}\,\,\,\,\,\,\,\,\,\,\,\,\,NO_{2}^{+}\,\,>\,\,N{{O}_{2}}\,\,>\,\,NO_{2}^{-} \\ & \text{Bond}\,\text{angle:}\,\,\,\,{{180}^{o}}\,\,\,\,\,\,\,\,\,{{135}^{o}}\,\,\,\,\,\,\,{{115}^{o}} \\ \end{align}\]
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