J & K CET Engineering J and K - CET Engineering Solved Paper-2004

  • question_answer
    The order and degree of the differential equation         \[y=\frac{dy}{dx}x+\sqrt{{{a}^{2}}{{\left( \frac{dy}{dx} \right)}^{2}}+{{b}^{2}}}\] is

    A)  \[3,1\]

    B)  \[1,2\]

    C)  \[2,1\]

    D)  \[1,3\]

    Correct Answer: B

    Solution :

    Given differential equation can be rewritten as \[y-x\,\,\frac{dy}{dx}=\sqrt{{{a}^{2}}{{\left( \frac{dy}{dx} \right)}^{2}}+{{b}^{2}}}\] On squaring both sides, we get \[{{y}^{2}}+{{\left( x\frac{dy}{dx} \right)}^{2}}-2yx\frac{dy}{dx}={{a}^{2}}{{\left( \frac{dy}{dx} \right)}^{2}}+{{b}^{2}}\] Here, order is 1 and degree is 2.


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