A) \[0\]
B) \[1\]
C) \[2\]
D) \[3\]
Correct Answer: B
Solution :
\[\int_{-1}^{1}{(x-[x])\,dx}\] \[=\int_{-1}^{0}{(x-[x])\,dx+\int_{0}^{1}{(x-[x])dx}}\] \[=\int_{-1}^{0}{(x+1)dx+\int_{0}^{1}{x\,\,dx}}\] \[=\left[ \frac{{{x}^{2}}}{2}+x \right]_{-1}^{0}+\left[ \frac{{{x}^{2}}}{2} \right]_{0}^{1}\] \[=0-\left( \frac{1}{2}-1 \right)+\frac{1}{2}=1\]
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