J & K CET Engineering J and K - CET Engineering Solved Paper-2004

  • question_answer
    If the vectors \[\vec{a}=(c\,\,{{\log }_{2}}\,x)\,\hat{i}-6\hat{j}+3\hat{k}\] and \[\vec{b}=({{\log }_{2}}x)\hat{i}+2\hat{j}+(2c\,{{\log }_{2}}\,x)\hat{k}\] make an obtuse angle for any \[x\,\in \,(0,\infty ),\] then the interval of which 'c? belongs

    A)  \[\left( \frac{4}{3},0 \right)\]

    B)  \[\left( -\frac{4}{3},0 \right)\]

    C)  \[\left( \frac{3}{4},0 \right)\]

    D)  \[\left( -\frac{3}{4},0 \right)\]

    Correct Answer: B

    Solution :

    We know that \[cso\,\theta =\frac{\vec{a}\,.\vec{b}}{|\vec{a}|\,|\vec{b}|}\] \[=\frac{c{{({{\log }_{2}}x)}^{2}}-12+6c\,{{\log }_{2}}x}{\left[ \begin{align}   & \sqrt{{{(c\,{{\log }_{2}}x)}^{2}}+36+9} \\  & \times \sqrt{{{({{\log }_{2}}x)}^{2}}+4+4{{(c\,{{\log }_{2}}x)}^{2}}} \\ \end{align} \right]}\] Since, angle is obtuse \[\therefore \] \[\cos \,\theta <0\] \[\Rightarrow \] \[c{{({{\log }_{2}}x)}^{2}}-12+6c\,{{\log }_{2}}x<0\] \[\Rightarrow \] \[c<0\]  and \[D<0\] \[\Rightarrow \] \[c<0\] and \[{{(6c)}^{2}}+48c<0\] \[\Rightarrow \] \[c<0\] and \[c<-\frac{4}{3}\] \[\therefore \] \[c\in \left( -\frac{4}{3},0 \right)\]


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