J & K CET Engineering J and K - CET Engineering Solved Paper-2004

  • question_answer
    The rank of the matrix \[\left| \begin{matrix}    4 & 2 & (1-x)  \\    5 & k & 1  \\    6 & 3 & (1+x)  \\ \end{matrix} \right|\] is 2, then

    A)  \[k=\frac{5}{2},\,x=\frac{1}{5}\]   

    B)  \[k=\frac{5}{2},\,x\ne \frac{1}{5}\]

    C)  \[k=\frac{1}{5},\,x=\frac{5}{2}\]   

    D)  None of these

    Correct Answer: A

    Solution :

    Let \[\Delta =\left| \begin{matrix}    4 & 2 & (1-x)  \\    5 & k & 1  \\    6 & 3 & (1+x)  \\ \end{matrix} \right|\] Applying \[{{R}_{1}}\to {{R}_{1}}+{{R}_{3}}\] \[\Rightarrow \] \[\Delta =\left| \begin{matrix}    10 & 5 & 2  \\    5 & k & 1  \\    6 & 3 & 1+x  \\ \end{matrix} \right|\] Applying \[{{C}_{1}}\to {{C}_{1}}-2{{C}_{2}}\] \[\Rightarrow \] \[\Delta =\left| \begin{matrix}    0 & 5 & 2  \\    5-2k & k & 1  \\    0 & 3 & 1+x  \\ \end{matrix} \right|\] \[\Rightarrow \] \[(5-2k)(5+5x-6)=0\] \[\Rightarrow \] \[(5-2k)(5+5x-6)=0\]


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