J & K CET Engineering J and K - CET Engineering Solved Paper-2004

  • question_answer
    A circle is inscribed in a equilateral triangle of side a. The area of the circle is

    A)  \[3\pi {{a}^{2}}\] sq unit    

    B)  \[2{{a}^{2}}\] sq unit

    C)  \[{{a}^{2}}\]sq unit      

    D)  None of these

    Correct Answer: A

    Solution :

    In an equilateral triangle length of median \[CD=\frac{\sqrt{3}}{2}a.\] Also, centroid of triangle lies on the centre of circle. \[\therefore \] \[OC=2\times \frac{\sqrt{3}}{2}a=\sqrt{3}a\] \[\therefore \] Area of circle =\[\pi {{(OC)}^{2}}\] \[=3\pi {{a}^{2}}\,\,sq\,\,unit\]


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