A) cold water
B) hot \[\text{NaOH}\]solution
C) dil \[{{\text{H}}_{\text{2}}}\text{S}{{\text{O}}_{\text{4}}}\]
D) dil \[\text{HCl}\]
Correct Answer: A
Solution :
Zinc, does not react with cold water. \[Zn+\underset{\text{steam}}{\mathop{{{H}_{2}}O}}\,\xrightarrow{{}}ZnO+{{H}_{2}}\uparrow \] \[Zn+2NaOH\xrightarrow{{}}N{{a}_{2}}Zn{{O}_{2}}+{{H}_{2}}\uparrow \] \[Zn+\underset{dil.}{\mathop{2HCl}}\,\xrightarrow{{}}ZnC{{l}_{2}}+{{H}_{2}}\uparrow \] \[Zn+\underset{dil.}{\mathop{{{H}_{2}}S{{O}_{4}}}}\,\xrightarrow{{}}ZnS{{O}_{4}}+{{H}_{2}}\uparrow \]
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