A) \[ClC{{H}_{2}}COOH\]
B) \[{{C}_{6}}{{H}_{5}}COOH\]
C) \[C{{D}_{3}}COOH\]
D) \[C{{H}_{3}}C{{H}_{2}}COOH\]
Correct Answer: A
Solution :
Any electron withdrawing group increases the acidity due to\[-I\]effect. The\[-I\]effect of chlorine is greater than phenyl group. Hence, \[ClC{{H}_{2}}COOH\]is the most acidic compound among these.
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