A) ethyl alcohol
B) ethyl bromide
C) bromobenzene
D) chlorobenzene
Correct Answer: B
Solution :
Ethyl bromide reacts with KCN to give ethyl cyanide, \[\underset{\text{ethyl}\,\text{bromide}}{\mathop{{{C}_{2}}{{H}_{5}}Br}}\,+KCN(alc.)\xrightarrow{{}}\underset{\text{ethyl}\,\text{cyanide}}{\mathop{{{\text{C}}_{\text{2}}}{{\text{H}}_{\text{5}}}\text{CN}}}\,\,+\,KBr\]
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